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=G^2-6G-12
We move all terms to the left:
-(G^2-6G-12)=0
We get rid of parentheses
-G^2+6G+12=0
We add all the numbers together, and all the variables
-1G^2+6G+12=0
a = -1; b = 6; c = +12;
Δ = b2-4ac
Δ = 62-4·(-1)·12
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{21}}{2*-1}=\frac{-6-2\sqrt{21}}{-2} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{21}}{2*-1}=\frac{-6+2\sqrt{21}}{-2} $
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